10=-2x^2+12x+7

Solution for 10=-2x^2+12x+7 equation:

10=-2x^2+12x+7

We move all terms to the left:

10-(-2x^2+12x+7)=0

We get rid of parentheses

2x^2-12x-7+10=0

We add all the numbers together, and all the variables

2x^2-12x+3=0

a = 2; b = -12; c = +3;
Δ = b2-4ac
Δ = -122-4·2·3
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{30}}{2*2}=\frac{12-2\sqrt{30}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{30}}{2*2}=\frac{12+2\sqrt{30}}{4}
$